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V838. Temporary object is...
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V838. Temporary object is constructed during lookup in ordered associative container. Consider using a container with heterogeneous lookup to avoid construction of temporary objects.

Aug 02 2023

The analyzer has detected a call to the lookup function in an ordered associative container ('std::set', 'std::multiset', 'std::map', or 'std::multimap') with an argument whose type differs from the container's key type. This call results in the creation of a temporary object with the key type from the passed argument.

If type conversion is an expensive operation (for example, 'const char *' to 'std::string'), it may affect application performance.

Starting with C++14, you can avoid creating a temporary object. This requires the comparator of the ordered associative container to support the heterogeneous lookup. For this to happen, the following conditions must be met:

  • The comparator is able to compare the argument type with the key type.
  • The 'is_transparent' alias is declared in the comparator.

The analyzer issues a warning if the 'is_transparent' name is not declared in the comparator.

Let's take a look at the example:

void foo(const char *str)
{
  static std::set<std::string> cont;

  auto it = cont.find(str); // <=
  if (it != cont.end())
  {
    // do smth
  }
}

In the example above, the 'cont' container is declared with the comparator of the 'std::less<std::string>' type by default. This comparator does not support heterogeneous lookup. Therefore, each call to the 'find' function creates a temporary 'std::string' object from 'const char *'.

To avoid creating a temporary object of the 'std::string' type, use a container with a comparator that supports heterogeneous lookup and can compare 'std::string' with 'const char *'. For example, you can use 'std::set' with the 'std::less<>' comparator:

void foo(const char *str)
{
  static std::set<std::string, std::less<>> cont;

  auto it = cont.find(str);
  if (it != cont.end())
  {
    // do smth
  }
}

Now, when calling the 'find' function, a temporary object of the 'std::string' type is not created, and an argument of the 'const char *' type is directly compared with the keys.

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